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暴力做法是对每个位置向右扫描找第一个更大值,O(n²)。可抽象为:元素像一排人,身高为数值。当前人「下一个更大」= 他右侧第一个没被挡住的人(比当前矮的都被挡住)。单调栈用 O(n) 维护「右侧候选更大值」:倒序遍历,弹掉 ≤ 当前的,栈顶即答案,再入栈当前值。

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Reporting by Chance Townsend, Caitlin Welsh, Sam Haysom, Amanda Yeo, Shannon Connellan, Cecily Mauran, Mike Pearl, and Adam Rosenberg contributed to this article.,更多细节参见搜狗输入法2026

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